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28n^2-24n=0
a = 28; b = -24; c = 0;
Δ = b2-4ac
Δ = -242-4·28·0
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-24}{2*28}=\frac{0}{56} =0 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+24}{2*28}=\frac{48}{56} =6/7 $
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